1863 Iowa gubernatorial election
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The 1863 Iowa gubernatorial election was held on 13 October 1863 in order to elect the Governor of Iowa. Republican nominee William M. Stone defeated Democratic nominee James M. Tuttle.[1]
General election
[edit]On election day, 13 October 1863, Republican nominee William M. Stone won the election by a margin of 29,949 votes against his opponent Democratic nominee James M. Tuttle, thereby holding Republican control over the office of Governor. Stone was sworn in as the 6th Governor of Iowa on 14 January 1864.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | William M. Stone | 86,118 | 60.51 | |
| Democratic | James M. Tuttle | 56,169 | 39.47 | |
| Scattering | 27 | 0.02 | ||
| Total votes | 142,314 | 100.00 | ||
| Republican hold | ||||
References
[edit]- ^ "William Milo Stone". National Governors Association. 13 January 1983. Retrieved 28 November 2023.
- ^ "IA Governor". ourcampaigns.com. 25 July 2005. Retrieved 28 November 2023.
- ^ Iowa General Assembly. Journal of the House of Representatives. 1864 sess., 3, accessed 28 November 2023