1978 Wendy's Tennis Classic

1978 Wendy's Tennis Classic
DateAugust 7–13
Edition9th
CategoryGrand Prix
Draw32S / 16D
Prize money$75,000
SurfaceClay / outdoor
LocationColumbus, Ohio, United States
VenueMuirfield Village
Champions
Singles
United States Arthur Ashe[1]
Doubles
Australia Colin Dibley / Australia Bob Giltinan[2]
← 1977 · Columbus Open · 1979 →

The 1978 Wendy's Tennis Classic, also known as the Buckeye Championships, was a men's tennis tournament played on outdoor clay courts at the Muirfield Village in Dublin, a suburb of Columbus, Ohio in the United States that was part of the 1978 Grand Prix circuit. It was the ninth edition of the tournament and was held from August 7 through August 13, 1978. Third-seeded Arthur Ashe won the singles title and earned $12,750 first-prize money.[3][4]

Finals

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Singles

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United States Arthur Ashe defeated United States Bob Lutz 6–3, 6–4

  • It was Ashe's 2nd singles title of the year and 75th of his career.

Doubles

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Australia Colin Dibley / Australia Bob Giltinan defeated Mexico Marcello Lara / United States Eliot Teltscher 6–2, 6–3

References

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  1. ^ "1978 Columbus – Singles draw". Association of Tennis Professionals (ATP).
  2. ^ "1978 Columbus – Doubles draw". Association of Tennis Professionals (ATP).
  3. ^ Dave Wohlfarth (August 14, 1978). "Lutz left in the 'Ashes'". The Journal Herald. p. 9 – via Newspapers.com.
  4. ^ John Barrett, ed. (1979). World of Tennis 1979 : a BP yearbook. London: Macdonald and Jane's. pp. 28, 123. ISBN 978-0354090681.
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