Polynomial sequence
Plot of the Chebyshev polynomial of the first kind T n(x) with n=5 in the complex plane from -2-2i to 2+2i with colors created with Mathematica 13.1 function ComplexPlot3D The Chebyshev polynomials are two sequences of polynomials related to the cosine and sine functions , notated as T n ( x ) {\displaystyle T_{n}(x)} and U n ( x ) {\displaystyle U_{n}(x)} . They can be defined in several equivalent ways, one of which starts with trigonometric functions :
The Chebyshev polynomials of the first kind T n {\displaystyle T_{n}} are defined by:
T n ( cos θ ) = cos ( n θ ) . {\displaystyle T_{n}(\cos \theta )=\cos(n\theta ).} Similarly, the Chebyshev polynomials of the second kind U n {\displaystyle U_{n}} are defined by:
U n ( cos θ ) sin θ = sin ( ( n + 1 ) θ ) . {\displaystyle U_{n}(\cos \theta )\sin \theta =\sin {\big (}(n+1)\theta {\big )}.} That these expressions define polynomials in cos θ {\displaystyle \cos \theta } may not be obvious at first sight but follows by rewriting cos ( n θ ) {\displaystyle \cos(n\theta )} and sin ( ( n + 1 ) θ ) {\displaystyle \sin {\big (}(n+1)\theta {\big )}} using de Moivre's formula or by using the angle sum formulas for cos {\displaystyle \cos } and sin {\displaystyle \sin } repeatedly. For example, the double angle formulas , which follow directly from the angle sum formulas, may be used to obtain T 2 ( cos θ ) = cos ( 2 θ ) = 2 cos 2 θ − 1 {\displaystyle T_{2}(\cos \theta )=\cos(2\theta )=2\cos ^{2}\theta -1} and U 1 ( cos θ ) sin θ = sin ( 2 θ ) = 2 cos θ sin θ {\displaystyle U_{1}(\cos \theta )\sin \theta =\sin(2\theta )=2\cos \theta \sin \theta } , which are respectively a polynomial in cos θ {\displaystyle \cos \theta } and a polynomial in cos θ {\displaystyle \cos \theta } multiplied by sin θ {\displaystyle \sin \theta } . Hence T 2 ( x ) = 2 x 2 − 1 {\displaystyle T_{2}(x)=2x^{2}-1} and U 1 ( x ) = 2 x {\displaystyle U_{1}(x)=2x} .
An important and convenient property of the Tn (x ) is that they are orthogonal with respect to the inner product :
⟨ f , g ⟩ = ∫ − 1 1 f ( x ) g ( x ) d x 1 − x 2 , {\displaystyle \langle f,g\rangle =\int _{-1}^{1}f(x)\,g(x)\,{\frac {\mathrm {d} x}{\sqrt {1-x^{2}}}},} and
U n (x ) are orthogonal with respect to another, analogous inner product, given below.
The Chebyshev polynomials Tn are polynomials with the largest possible leading coefficient whose absolute value on the interval [−1, 1] is bounded by 1. They are also the "extremal" polynomials for many other properties.[1]
In 1952, Cornelius Lanczos showed that the Chebyshev polynomials are important in approximation theory for the solution of linear systems;[2] the roots of Tn (x ) , which are also called Chebyshev nodes , are used as matching points for optimizing polynomial interpolation . The resulting interpolation polynomial minimizes the problem of Runge's phenomenon and provides an approximation that is close to the best polynomial approximation to a continuous function under the maximum norm , also called the "minimax " criterion. This approximation leads directly to the method of Clenshaw–Curtis quadrature .
These polynomials were named after Pafnuty Chebyshev .[3] The letter T is used because of the alternative transliterations of the name Chebyshev as Tchebycheff , Tchebyshev (French) or Tschebyschow (German).
Definitions [ edit ] Recurrence definition [ edit ] Plot of the first five Tn Chebyshev polynomials (first kind) The Chebyshev polynomials of the first kind are obtained from the recurrence relation :
T 0 ( x ) = 1 T 1 ( x ) = x T n + 1 ( x ) = 2 x T n ( x ) − T n − 1 ( x ) . {\displaystyle {\begin{aligned}T_{0}(x)&=1\\T_{1}(x)&=x\\T_{n+1}(x)&=2x\,T_{n}(x)-T_{n-1}(x).\end{aligned}}} The recurrence also allows to represent them explicitly as the determinant of a
tridiagonal matrix of size
k × k {\displaystyle k\times k} :
T k ( x ) = det [ x 1 0 ⋯ 0 1 2 x 1 ⋱ ⋮ 0 1 2 x ⋱ 0 ⋮ ⋱ ⋱ ⋱ 1 0 ⋯ 0 1 2 x ] {\displaystyle T_{k}(x)=\det {\begin{bmatrix}x&1&0&\cdots &0\\1&2x&1&\ddots &\vdots \\0&1&2x&\ddots &0\\\vdots &\ddots &\ddots &\ddots &1\\0&\cdots &0&1&2x\end{bmatrix}}} The ordinary generating function for Tn is:
∑ n = 0 ∞ T n ( x ) t n = 1 − t x 1 − 2 t x + t 2 . {\displaystyle \sum _{n=0}^{\infty }T_{n}(x)\,t^{n}={\frac {1-tx}{1-2tx+t^{2}}}.} There are several other
generating functions for the Chebyshev polynomials; the
exponential generating function is:
∑ n = 0 ∞ T n ( x ) t n n ! = 1 2 ( e t ( x − x 2 − 1 ) + e t ( x + x 2 − 1 ) ) = e t x cosh ( t x 2 − 1 ) . {\displaystyle \sum _{n=0}^{\infty }T_{n}(x){\frac {t^{n}}{n!}}={\frac {1}{2}}\!\left(e^{t\left(x-{\sqrt {x^{2}-1}}\right)}+e^{t\left(x+{\sqrt {x^{2}-1}}\right)}\right)=e^{tx}\cosh \left(t{\sqrt {x^{2}-1}}\right).} The generating function relevant for 2-dimensional potential theory and multipole expansion is:
∑ n = 1 ∞ T n ( x ) t n n = ln ( 1 1 − 2 t x + t 2 ) . {\displaystyle \sum \limits _{n=1}^{\infty }T_{n}(x)\,{\frac {t^{n}}{n}}=\ln \left({\frac {1}{\sqrt {1-2tx+t^{2}}}}\right).} Plot of the first five Un Chebyshev polynomials (second kind) The Chebyshev polynomials of the second kind are defined by the recurrence relation:
U 0 ( x ) = 1 U 1 ( x ) = 2 x U n + 1 ( x ) = 2 x U n ( x ) − U n − 1 ( x ) . {\displaystyle {\begin{aligned}U_{0}(x)&=1\\U_{1}(x)&=2x\\U_{n+1}(x)&=2x\,U_{n}(x)-U_{n-1}(x).\end{aligned}}} Notice that the two sets of recurrence relations are identical, except for
T 1 ( x ) = x {\displaystyle T_{1}(x)=x} vs.
U 1 ( x ) = 2 x {\displaystyle U_{1}(x)=2x} . The ordinary generating function for
Un is:
∑ n = 0 ∞ U n ( x ) t n = 1 1 − 2 t x + t 2 , {\displaystyle \sum _{n=0}^{\infty }U_{n}(x)\,t^{n}={\frac {1}{1-2tx+t^{2}}},} and the exponential generating function is:
∑ n = 0 ∞ U n ( x ) t n n ! = e t x ( cosh ( t x 2 − 1 ) + x x 2 − 1 sinh ( t x 2 − 1 ) ) . {\displaystyle \sum _{n=0}^{\infty }U_{n}(x){\frac {t^{n}}{n!}}=e^{tx}\!\left(\!\cosh \left(t{\sqrt {x^{2}-1}}\right)+{\frac {x}{\sqrt {x^{2}-1}}}\sinh \left(t{\sqrt {x^{2}-1}}\right)\!\right).} Trigonometric definition [ edit ] As described in the introduction, the Chebyshev polynomials of the first kind can be defined as the unique polynomials satisfying:
T n ( x ) = { cos ( n arccos x ) if | x | ≤ 1 cosh ( n arcosh x ) if x ≥ 1 ( − 1 ) n cosh ( n arcosh ( − x ) ) if x ≤ − 1 {\displaystyle T_{n}(x)={\begin{cases}\cos(n\arccos x)&{\text{ if }}~|x|\leq 1\\\cosh(n\operatorname {arcosh} x)&{\text{ if }}~x\geq 1\\(-1)^{n}\cosh(n\operatorname {arcosh} (-x))&{\text{ if }}~x\leq -1\end{cases}}} or, in other words, as the unique polynomials satisfying:
T n ( cos θ ) = cos ( n θ ) {\displaystyle T_{n}(\cos \theta )=\cos(n\theta )} for
n = 0, 1, 2, 3, ….
The polynomials of the second kind satisfy:
U n − 1 ( cos θ ) sin θ = sin ( n θ ) , {\displaystyle U_{n-1}(\cos \theta )\sin \theta =\sin(n\theta ),} or
U n ( cos θ ) = sin ( ( n + 1 ) θ ) sin θ , {\displaystyle U_{n}(\cos \theta )={\frac {\sin {\big (}(n+1)\,\theta {\big )}}{\sin \theta }},} which is structurally quite similar to the
Dirichlet kernel D n (x ):
D n ( x ) = sin ( ( 2 n + 1 ) x 2 ) sin x 2 = U 2 n ( cos x 2 ) . {\displaystyle D_{n}(x)={\frac {\sin \left((2n+1){\dfrac {x}{2}}\,\right)}{\sin {\dfrac {x}{2}}}}=U_{2n}\!\!\left(\cos {\frac {x}{2}}\right).} (The Dirichlet kernel, in fact, coincides with what is now known as the
Chebyshev polynomial of the fourth kind .)
An equivalent way to state this is via exponentiation of a complex number : given a complex number z = a + bi with absolute value of one:
z n = T n ( a ) + i b U n − 1 ( a ) . {\displaystyle z^{n}=T_{n}(a)+ibU_{n-1}(a).} Chebyshev polynomials can be defined in this form when studying
trigonometric polynomials .
[4] That cos nx is an n th-degree polynomial in cos x can be seen by observing that cos nx is the real part of one side of de Moivre's formula :
cos n θ + i sin n θ = ( cos θ + i sin θ ) n . {\displaystyle \cos n\theta +i\sin n\theta =(\cos \theta +i\sin \theta )^{n}.} The real part of the other side is a polynomial in
cos x and
sin x , in which all powers of
sin x are
even and thus replaceable through the identity
cos2 x + sin2 x = 1 . By the same reasoning,
sin nx is the
imaginary part of the polynomial, in which all powers of
sin x are
odd and thus, if one factor of
sin x is factored out, the remaining factors can be replaced to create a
(n −1) st-degree polynomial in
cos x .
Commuting polynomials definition [ edit ] Chebyshev polynomials can also be characterized by the following theorem:[5]
If F n ( x ) {\displaystyle F_{n}(x)} is a family of monic polynomials with coefficients in a field of characteristic 0 {\displaystyle 0} such that deg F n ( x ) = n {\displaystyle \deg F_{n}(x)=n} and F m ( F n ( x ) ) = F n ( F m ( x ) ) {\displaystyle F_{m}(F_{n}(x))=F_{n}(F_{m}(x))} for all m {\displaystyle m} and n {\displaystyle n} , then, up to a simple change of variables, either F n ( x ) = x n {\displaystyle F_{n}(x)=x^{n}} for all n {\displaystyle n} or F n ( x ) = 2 ∗ T n ( x / 2 ) {\displaystyle F_{n}(x)=2*T_{n}(x/2)} for all n {\displaystyle n} .
Pell equation definition [ edit ] The Chebyshev polynomials can also be defined as the solutions to the Pell equation :
T n ( x ) 2 − ( x 2 − 1 ) U n − 1 ( x ) 2 = 1 {\displaystyle T_{n}(x)^{2}-\left(x^{2}-1\right)U_{n-1}(x)^{2}=1} in a
ring R [x ].
[6] Thus, they can be generated by the standard technique for Pell equations of taking powers of a fundamental solution:
T n ( x ) + U n − 1 ( x ) x 2 − 1 = ( x + x 2 − 1 ) n . {\displaystyle T_{n}(x)+U_{n-1}(x)\,{\sqrt {x^{2}-1}}=\left(x+{\sqrt {x^{2}-1}}\right)^{n}~.} Relations between the two kinds of Chebyshev polynomials [ edit ] The Chebyshev polynomials of the first and second kinds correspond to a complementary pair of Lucas sequences Ṽn (P , Q ) and Ũn (P , Q ) with parameters P = 2x and Q = 1 :
U ~ n ( 2 x , 1 ) = U n − 1 ( x ) , V ~ n ( 2 x , 1 ) = 2 T n ( x ) . {\displaystyle {\begin{aligned}{\tilde {U}}_{n}(2x,1)&=U_{n-1}(x),\\{\tilde {V}}_{n}(2x,1)&=2\,T_{n}(x).\end{aligned}}} It follows that they also satisfy a pair of mutual recurrence equations:
[7] T n + 1 ( x ) = x T n ( x ) − ( 1 − x 2 ) U n − 1 ( x ) , U n + 1 ( x ) = x U n ( x ) + T n + 1 ( x ) . {\displaystyle {\begin{aligned}T_{n+1}(x)&=x\,T_{n}(x)-(1-x^{2})\,U_{n-1}(x),\\U_{n+1}(x)&=x\,U_{n}(x)+T_{n+1}(x).\end{aligned}}} The second of these may be rearranged using the recurrence definition for the Chebyshev polynomials of the second kind to give:
T n ( x ) = 1 2 ( U n ( x ) − U n − 2 ( x ) ) . {\displaystyle T_{n}(x)={\frac {1}{2}}{\big (}U_{n}(x)-U_{n-2}(x){\big )}.} Using this formula iteratively gives the sum formula:
U n ( x ) = { 2 ∑ odd j n T j ( x ) for odd n . 2 ∑ even j n T j ( x ) + 1 for even n , {\displaystyle U_{n}(x)={\begin{cases}2\sum _{{\text{ odd }}j}^{n}T_{j}(x)&{\text{ for odd }}n.\\2\sum _{{\text{ even }}j}^{n}T_{j}(x)+1&{\text{ for even }}n,\end{cases}}} while replacing
U n ( x ) {\displaystyle U_{n}(x)} and
U n − 2 ( x ) {\displaystyle U_{n-2}(x)} using the
derivative formula for
T n ( x ) {\displaystyle T_{n}(x)} gives the recurrence relationship for the derivative of
T n {\displaystyle T_{n}} :
2 T n ( x ) = 1 n + 1 d d x T n + 1 ( x ) − 1 n − 1 d d x T n − 1 ( x ) , n = 2 , 3 , … {\displaystyle 2\,T_{n}(x)={\frac {1}{n+1}}\,{\frac {\mathrm {d} }{\mathrm {d} x}}\,T_{n+1}(x)-{\frac {1}{n-1}}\,{\frac {\mathrm {d} }{\mathrm {d} x}}\,T_{n-1}(x),\qquad n=2,3,\ldots } This relationship is used in the Chebyshev spectral method of solving differential equations.
Turán's inequalities for the Chebyshev polynomials are:[8]
T n ( x ) 2 − T n − 1 ( x ) T n + 1 ( x ) = 1 − x 2 > 0 for − 1 < x < 1 and U n ( x ) 2 − U n − 1 ( x ) U n + 1 ( x ) = 1 > 0 . {\displaystyle {\begin{aligned}T_{n}(x)^{2}-T_{n-1}(x)\,T_{n+1}(x)&=1-x^{2}>0&&{\text{ for }}-1<x<1&&{\text{ and }}\\U_{n}(x)^{2}-U_{n-1}(x)\,U_{n+1}(x)&=1>0~.\end{aligned}}} The integral relations are[7] : 187(47)(48) [9]
∫ − 1 1 T n ( y ) y − x d y 1 − y 2 = π U n − 1 ( x ) , ∫ − 1 1 U n − 1 ( y ) y − x 1 − y 2 d y = − π T n ( x ) {\displaystyle {\begin{aligned}\int _{-1}^{1}{\frac {T_{n}(y)}{y-x}}\,{\frac {\mathrm {d} y}{\sqrt {1-y^{2}}}}&=\pi \,U_{n-1}(x)~,\\[1.5ex]\int _{-1}^{1}{\frac {U_{n-1}(y)}{y-x}}\,{\sqrt {1-y^{2}}}\mathrm {d} y&=-\pi \,T_{n}(x)\end{aligned}}} where integrals are considered as principal value.
Explicit expressions [ edit ] Different approaches to defining Chebyshev polynomials lead to different explicit expressions. The trigonometric definition gives an explicit formula as follows:
T n ( x ) = { cos ( n arccos x ) for − 1 ≤ x ≤ 1 cosh ( n arcosh x ) for 1 ≤ x ( − 1 ) n cosh ( n arcosh ( − x ) ) for x ≤ − 1 {\displaystyle {\begin{aligned}T_{n}(x)&={\begin{cases}\cos(n\arccos x)\qquad \quad &{\text{ for }}~-1\leq x\leq 1\\\cosh(n\operatorname {arcosh} x)\qquad \quad &{\text{ for }}~1\leq x\\(-1)^{n}\cosh {\big (}n\operatorname {arcosh} (-x){\big )}\qquad \quad &{\text{ for }}~x\leq -1\end{cases}}\end{aligned}}} From this trigonometric form, the recurrence definition can be recovered by computing directly that the bases cases hold:
T 0 ( cos θ ) = cos ( 0 θ ) = 1 {\displaystyle T_{0}(\cos \theta )=\cos(0\theta )=1} and
T 1 ( cos θ ) = cos θ , {\displaystyle T_{1}(\cos \theta )=\cos \theta ,} and that the
product-to-sum identity holds:
2 cos n θ cos θ = cos [ ( n + 1 ) θ ] + cos [ ( n − 1 ) θ ] . {\displaystyle 2\cos n\theta \cos \theta =\cos \lbrack (n+1)\theta \rbrack +\cos \lbrack (n-1)\theta \rbrack .} Using the complex number exponentiation definition of the Chebyshev polynomial, one can derive the following expression:
T n ( x ) = 1 2 ( ( x − x 2 − 1 ) n + ( x + x 2 − 1 ) n ) for x ∈ R {\displaystyle T_{n}(x)={\dfrac {1}{2}}{\bigg (}{\Big (}x-{\sqrt {x^{2}-1}}{\Big )}^{n}+{\Big (}x+{\sqrt {x^{2}-1}}{\Big )}^{n}{\bigg )}\qquad {\text{ for }}~x\in \mathbb {R} } T n ( x ) = 1 2 ( ( x − x 2 − 1 ) n + ( x − x 2 − 1 ) − n ) for x ∈ R {\displaystyle T_{n}(x)={\dfrac {1}{2}}{\bigg (}{\Big (}x-{\sqrt {x^{2}-1}}{\Big )}^{n}+{\Big (}x-{\sqrt {x^{2}-1}}{\Big )}^{-n}{\bigg )}\qquad {\text{ for }}~x\in \mathbb {R} } The two are equivalent because
( x + x 2 − 1 ) ( x − x 2 − 1 ) = 1 {\displaystyle (x+{\sqrt {x^{2}-1}})(x-{\sqrt {x^{2}-1}})=1} .
An explicit form of the Chebyshev polynomial in terms of monomials x k follows from de Moivre's formula :
T n ( cos ( θ ) ) = Re ( cos n θ + i sin n θ ) = Re ( ( cos θ + i sin θ ) n ) , {\displaystyle T_{n}(\cos(\theta ))=\operatorname {Re} (\cos n\theta +i\sin n\theta )=\operatorname {Re} ((\cos \theta +i\sin \theta )^{n}),} where
Re denotes the
real part of a complex number. Expanding the formula, one gets:
( cos θ + i sin θ ) n = ∑ j = 0 n ( n j ) i j sin j θ cos n − j θ . {\displaystyle (\cos \theta +i\sin \theta )^{n}=\sum \limits _{j=0}^{n}{\binom {n}{j}}i^{j}\sin ^{j}\theta \cos ^{n-j}\theta .} The real part of the expression is obtained from summands corresponding to even indices. Noting
i 2 j = ( − 1 ) j {\displaystyle i^{2j}=(-1)^{j}} and
sin 2 j θ = ( 1 − cos 2 θ ) j {\displaystyle \sin ^{2j}\theta =(1-\cos ^{2}\theta )^{j}} , one gets the explicit formula:
cos n θ = ∑ j = 0 ⌊ n / 2 ⌋ ( n 2 j ) ( cos 2 θ − 1 ) j cos n − 2 j θ , {\displaystyle \cos n\theta =\sum \limits _{j=0}^{\lfloor n/2\rfloor }{\binom {n}{2j}}(\cos ^{2}\theta -1)^{j}\cos ^{n-2j}\theta ,} which in turn means that:
T n ( x ) = ∑ j = 0 ⌊ n / 2 ⌋ ( n 2 j ) ( x 2 − 1 ) j x n − 2 j . {\displaystyle T_{n}(x)=\sum \limits _{j=0}^{\lfloor n/2\rfloor }{\binom {n}{2j}}(x^{2}-1)^{j}x^{n-2j}.} This can be written as a
2 F 1 hypergeometric function :
T n ( x ) = ∑ k = 0 ⌊ n 2 ⌋ ( n 2 k ) ( x 2 − 1 ) k x n − 2 k = x n ∑ k = 0 ⌊ n 2 ⌋ ( n 2 k ) ( 1 − x − 2 ) k = n 2 ∑ k = 0 ⌊ n 2 ⌋ ( − 1 ) k ( n − k − 1 ) ! k ! ( n − 2 k ) ! ( 2 x ) n − 2 k for n > 0 = n ∑ k = 0 n ( − 2 ) k ( n + k − 1 ) ! ( n − k ) ! ( 2 k ) ! ( 1 − x ) k for n > 0 = 2 F 1 ( − n , n ; 1 2 ; 1 2 ( 1 − x ) ) {\displaystyle {\begin{aligned}T_{n}(x)&=\sum _{k=0}^{\left\lfloor {\frac {n}{2}}\right\rfloor }{\binom {n}{2k}}\left(x^{2}-1\right)^{k}x^{n-2k}\\&=x^{n}\sum _{k=0}^{\left\lfloor {\frac {n}{2}}\right\rfloor }{\binom {n}{2k}}\left(1-x^{-2}\right)^{k}\\&={\frac {n}{2}}\sum _{k=0}^{\left\lfloor {\frac {n}{2}}\right\rfloor }(-1)^{k}{\frac {(n-k-1)!}{k!(n-2k)!}}~(2x)^{n-2k}\qquad \qquad {\text{ for }}~n>0\\\\&=n\sum _{k=0}^{n}(-2)^{k}{\frac {(n+k-1)!}{(n-k)!(2k)!}}(1-x)^{k}\qquad \qquad ~{\text{ for }}~n>0\\\\&={}_{2}F_{1}\!\left(-n,n;{\tfrac {1}{2}};{\tfrac {1}{2}}(1-x)\right)\\\end{aligned}}} with inverse:
[10] [11]
x n = 2 1 − n ∑ ′ j = 0 j ≡ n ( mod 2 ) n ( n n − j 2 ) T j ( x ) , {\displaystyle x^{n}=2^{1-n}\mathop {{\sum }'} _{j=0 \atop j\,\equiv \,n{\pmod {2}}}^{n}\!\!{\binom {n}{\tfrac {n-j}{2}}}\!\;T_{j}(x),} where the prime at the summation symbol indicates that the contribution of
j = 0 needs to be halved if it appears.
A related expression for T n as a sum of monomials with binomial coefficients and powers of two is
T n ( x ) = ∑ m = 0 ⌊ n 2 ⌋ ( − 1 ) m ( ( n − m m ) + ( n − m − 1 n − 2 m ) ) ⋅ 2 n − 2 m − 1 ⋅ x n − 2 m . {\displaystyle T_{n}\left(x\right)=\sum \limits _{m=0}^{\left\lfloor {\frac {n}{2}}\right\rfloor }\left(-1\right)^{m}\left({\binom {n-m}{m}}+{\binom {n-m-1}{n-2m}}\right)\cdot 2^{n-2m-1}\cdot x^{n-2m}.} Similarly, U n can be expressed in terms of hypergeometric functions:
U n ( x ) = ( x + x 2 − 1 ) n + 1 − ( x − x 2 − 1 ) n + 1 2 x 2 − 1 = ∑ k = 0 ⌊ n / 2 ⌋ ( n + 1 2 k + 1 ) ( x 2 − 1 ) k x n − 2 k = x n ∑ k = 0 ⌊ n / 2 ⌋ ( n + 1 2 k + 1 ) ( 1 − x − 2 ) k = ∑ k = 0 ⌊ n / 2 ⌋ ( 2 k − ( n + 1 ) k ) ( 2 x ) n − 2 k for n > 0 = ∑ k = 0 ⌊ n / 2 ⌋ ( − 1 ) k ( n − k k ) ( 2 x ) n − 2 k for n > 0 = ∑ k = 0 n ( − 2 ) k ( n + k + 1 ) ! ( n − k ) ! ( 2 k + 1 ) ! ( 1 − x ) k for n > 0 = ( n + 1 ) 2 F 1 ( − n , n + 2 ; 3 2 ; 1 2 ( 1 − x ) ) . {\displaystyle {\begin{aligned}U_{n}(x)&={\frac {\left(x+{\sqrt {x^{2}-1}}\right)^{n+1}-\left(x-{\sqrt {x^{2}-1}}\right)^{n+1}}{2{\sqrt {x^{2}-1}}}}\\&=\sum _{k=0}^{\left\lfloor {n}/{2}\right\rfloor }{\binom {n+1}{2k+1}}\left(x^{2}-1\right)^{k}x^{n-2k}\\&=x^{n}\sum _{k=0}^{\left\lfloor {n}/{2}\right\rfloor }{\binom {n+1}{2k+1}}\left(1-x^{-2}\right)^{k}\\&=\sum _{k=0}^{\left\lfloor {n}/{2}\right\rfloor }{\binom {2k-(n+1)}{k}}~(2x)^{n-2k}&{\text{ for }}~n>0\\&=\sum _{k=0}^{\left\lfloor {n}/{2}\right\rfloor }(-1)^{k}{\binom {n-k}{k}}~(2x)^{n-2k}&{\text{ for }}~n>0\\&=\sum _{k=0}^{n}(-2)^{k}{\frac {(n+k+1)!}{(n-k)!(2k+1)!}}(1-x)^{k}&{\text{ for }}~n>0\\&=(n+1)\ {}_{2}F_{1}\left(-n,n+2;{\tfrac {3}{2}};{\tfrac {1}{2}}(1-x)\right).\\\end{aligned}}} Properties [ edit ] Symmetry [ edit ]
T n ( − x ) = ( − 1 ) n T n ( x ) = { T n ( x ) for n even − T n ( x ) for n odd U n ( − x ) = ( − 1 ) n U n ( x ) = { U n ( x ) for n even − U n ( x ) for n odd {\displaystyle {\begin{aligned}T_{n}(-x)&=(-1)^{n}\,T_{n}(x)={\begin{cases}T_{n}(x)\quad &~{\text{ for }}~n~{\text{ even}}\\-T_{n}(x)\quad &~{\text{ for }}~n~{\text{ odd}}\end{cases}}\\\\U_{n}(-x)&=(-1)^{n}\,U_{n}(x)={\begin{cases}U_{n}(x)\quad &~{\text{ for }}~n~{\text{ even}}\\-U_{n}(x)\quad &~{\text{ for }}~n~{\text{ odd}}\end{cases}}\end{aligned}}} That is, Chebyshev polynomials of even order have even symmetry and therefore contain only even powers of x . Chebyshev polynomials of odd order have odd symmetry and therefore contain only odd powers of x .
Roots and extrema [ edit ] A Chebyshev polynomial of either kind with degree n has n different simple roots , called Chebyshev roots , in the interval [−1, 1] . The roots of the Chebyshev polynomial of the first kind are sometimes called Chebyshev nodes because they are used as nodes in polynomial interpolation. Using the trigonometric definition and the fact that:
cos ( ( 2 k + 1 ) π 2 ) = 0 {\displaystyle \cos \left((2k+1){\frac {\pi }{2}}\right)=0} one can show that the roots of
Tn are:
x k = cos ( π ( k + 1 / 2 ) n ) , k = 0 , … , n − 1. {\displaystyle x_{k}=\cos \left({\frac {\pi (k+1/2)}{n}}\right),\quad k=0,\ldots ,n-1.} Similarly, the roots of
Un are:
x k = cos ( k n + 1 π ) , k = 1 , … , n . {\displaystyle x_{k}=\cos \left({\frac {k}{n+1}}\pi \right),\quad k=1,\ldots ,n.} The
extrema of
Tn on the interval
−1 ≤ x ≤ 1 are located at:
x k = cos ( k n π ) , k = 0 , … , n . {\displaystyle x_{k}=\cos \left({\frac {k}{n}}\pi \right),\quad k=0,\ldots ,n.} One unique property of the Chebyshev polynomials of the first kind is that on the interval −1 ≤ x ≤ 1 all of the extrema have values that are either −1 or 1. Thus these polynomials have only two finite critical values , the defining property of Shabat polynomials . Both the first and second kinds of Chebyshev polynomial have extrema at the endpoints, given by:
T n ( 1 ) = 1 T n ( − 1 ) = ( − 1 ) n U n ( 1 ) = n + 1 U n ( − 1 ) = ( − 1 ) n ( n + 1 ) . {\displaystyle {\begin{aligned}T_{n}(1)&=1\\T_{n}(-1)&=(-1)^{n}\\U_{n}(1)&=n+1\\U_{n}(-1)&=(-1)^{n}(n+1).\end{aligned}}} The extrema of T n ( x ) {\displaystyle T_{n}(x)} on the interval − 1 ≤ x ≤ 1 {\displaystyle -1\leq x\leq 1} where n > 0 {\displaystyle n>0} are located at n + 1 {\displaystyle n+1} values of x {\displaystyle x} . They are ± 1 {\displaystyle \pm 1} , or cos ( 2 π k d ) {\displaystyle \cos \left({\frac {2\pi k}{d}}\right)} where d > 2 {\displaystyle d>2} , d | 2 n {\displaystyle d\;|\;2n} , 0 < k < d / 2 {\displaystyle 0<k<d/2} and ( k , d ) = 1 {\displaystyle (k,d)=1} , i.e., k {\displaystyle k} and d {\displaystyle d} are relatively prime numbers.
Specifically,[12] [13] when n {\displaystyle n} is even:
T n ( x ) = 1 {\displaystyle T_{n}(x)=1} if x = ± 1 {\displaystyle x=\pm 1} , or d > 2 {\displaystyle d>2} and 2 n / d {\displaystyle 2n/d} is even. There are n / 2 + 1 {\displaystyle n/2+1} such values of x {\displaystyle x} . T n ( x ) = − 1 {\displaystyle T_{n}(x)=-1} if d > 2 {\displaystyle d>2} and 2 n / d {\displaystyle 2n/d} is odd. There are n / 2 {\displaystyle n/2} such values of x {\displaystyle x} . When n {\displaystyle n} is odd:
T n ( x ) = 1 {\displaystyle T_{n}(x)=1} if x = 1 {\displaystyle x=1} , or d > 2 {\displaystyle d>2} and 2 n / d {\displaystyle 2n/d} is even. There are ( n + 1 ) / 2 {\displaystyle (n+1)/2} such values of x {\displaystyle x} . T n ( x ) = − 1 {\displaystyle T_{n}(x)=-1} if x = − 1 {\displaystyle x=-1} , or d > 2 {\displaystyle d>2} and 2 n / d {\displaystyle 2n/d} is odd. There are ( n + 1 ) / 2 {\displaystyle (n+1)/2} such values of x {\displaystyle x} . This result has been generalized to solutions of U n ( x ) ± 1 = 0 {\displaystyle U_{n}(x)\pm 1=0} ,[13] and to V n ( x ) ± 1 = 0 {\displaystyle V_{n}(x)\pm 1=0} and W n ( x ) ± 1 = 0 {\displaystyle W_{n}(x)\pm 1=0} for Chebyshev polynomials of the third and fourth kinds, respectively.[14]
Differentiation and integration [ edit ] The derivatives of the polynomials can be less than straightforward. By differentiating the polynomials in their trigonometric forms, it can be shown that:
d T n d x = n U n − 1 d U n d x = ( n + 1 ) T n + 1 − x U n x 2 − 1 d 2 T n d x 2 = n n T n − x U n − 1 x 2 − 1 = n ( n + 1 ) T n − U n x 2 − 1 . {\displaystyle {\begin{aligned}{\frac {\mathrm {d} T_{n}}{\mathrm {d} x}}&=nU_{n-1}\\{\frac {\mathrm {d} U_{n}}{\mathrm {d} x}}&={\frac {(n+1)T_{n+1}-xU_{n}}{x^{2}-1}}\\{\frac {\mathrm {d} ^{2}T_{n}}{\mathrm {d} x^{2}}}&=n\,{\frac {nT_{n}-xU_{n-1}}{x^{2}-1}}=n\,{\frac {(n+1)T_{n}-U_{n}}{x^{2}-1}}.\end{aligned}}} The last two formulas can be numerically troublesome due to the division by zero (0 / 0 indeterminate form , specifically) at x = 1 and x = −1 . By L'Hôpital's rule :
d 2 T n d x 2 | x = 1 = n 4 − n 2 3 , d 2 T n d x 2 | x = − 1 = ( − 1 ) n n 4 − n 2 3 . {\displaystyle {\begin{aligned}\left.{\frac {\mathrm {d} ^{2}T_{n}}{\mathrm {d} x^{2}}}\right|_{x=1}\!\!&={\frac {n^{4}-n^{2}}{3}},\\\left.{\frac {\mathrm {d} ^{2}T_{n}}{\mathrm {d} x^{2}}}\right|_{x=-1}\!\!&=(-1)^{n}{\frac {n^{4}-n^{2}}{3}}.\end{aligned}}} More generally,
d p T n d x p | x = ± 1 = ( ± 1 ) n + p ∏ k = 0 p − 1 n 2 − k 2 2 k + 1 , {\displaystyle \left.{\frac {d^{p}T_{n}}{dx^{p}}}\right|_{x=\pm 1}\!\!=(\pm 1)^{n+p}\prod _{k=0}^{p-1}{\frac {n^{2}-k^{2}}{2k+1}}~,} which is of great use in the numerical solution of
eigenvalue problems.
Also, we have:
d p d x p T n ( x ) = 2 p n ∑ ′ 0 ≤ k ≤ n − p k ≡ n − p ( mod 2 ) ( n + p − k 2 − 1 n − p − k 2 ) ( n + p + k 2 − 1 ) ! ( n − p + k 2 ) ! T k ( x ) , p ≥ 1 , {\displaystyle {\frac {\mathrm {d} ^{p}}{\mathrm {d} x^{p}}}\,T_{n}(x)=2^{p}\,n\mathop {{\sum }'} _{0\leq k\leq n-p \atop k\,\equiv \,n-p{\pmod {2}}}{\binom {{\frac {n+p-k}{2}}-1}{\frac {n-p-k}{2}}}{\frac {\left({\frac {n+p+k}{2}}-1\right)!}{\left({\frac {n-p+k}{2}}\right)!}}\,T_{k}(x),~\qquad p\geq 1,} where the prime at the summation symbols means that the term contributed by
k = 0 is to be halved, if it appears.
Concerning integration, the first derivative of the Tn implies that:
∫ U n d x = T n + 1 n + 1 {\displaystyle \int U_{n}\,\mathrm {d} x={\frac {T_{n+1}}{n+1}}} and the recurrence relation for the first kind polynomials involving derivatives establishes that for
n ≥ 2:
∫ T n d x = 1 2 ( T n + 1 n + 1 − T n − 1 n − 1 ) = n T n + 1 n 2 − 1 − x T n n − 1 . {\displaystyle \int T_{n}\,\mathrm {d} x={\frac {1}{2}}\,\left({\frac {T_{n+1}}{n+1}}-{\frac {T_{n-1}}{n-1}}\right)={\frac {n\,T_{n+1}}{n^{2}-1}}-{\frac {x\,T_{n}}{n-1}}.} The last formula can be further manipulated to express the integral of Tn as a function of Chebyshev polynomials of the first kind only:
∫ T n d x = n n 2 − 1 T n + 1 − 1 n − 1 T 1 T n = n n 2 − 1 T n + 1 − 1 2 ( n − 1 ) ( T n + 1 + T n − 1 ) = 1 2 ( n + 1 ) T n + 1 − 1 2 ( n − 1 ) T n − 1 . {\displaystyle {\begin{aligned}\int T_{n}\,\mathrm {d} x&={\frac {n}{n^{2}-1}}T_{n+1}-{\frac {1}{n-1}}T_{1}T_{n}\\&={\frac {n}{n^{2}-1}}\,T_{n+1}-{\frac {1}{2(n-1)}}\,(T_{n+1}+T_{n-1})\\&={\frac {1}{2(n+1)}}\,T_{n+1}-{\frac {1}{2(n-1)}}\,T_{n-1}.\end{aligned}}} Furthermore, we have:
∫ − 1 1 T n ( x ) d x = { ( − 1 ) n + 1 1 − n 2 if n ≠ 1 0 if n = 1. {\displaystyle \int _{-1}^{1}T_{n}(x)\,\mathrm {d} x={\begin{cases}{\frac {(-1)^{n}+1}{1-n^{2}}}&{\text{ if }}~n\neq 1\\0&{\text{ if }}~n=1.\end{cases}}} Products of Chebyshev polynomials [ edit ] The Chebyshev polynomials of the first kind satisfy the relation:
T m ( x ) T n ( x ) = 1 2 ( T m + n ( x ) + T | m − n | ( x ) ) , ∀ m , n ≥ 0 , {\displaystyle T_{m}(x)\,T_{n}(x)={\tfrac {1}{2}}\!\left(T_{m+n}(x)+T_{|m-n|}(x)\right)\!,\qquad \forall m,n\geq 0,} which is easily proved from the
product-to-sum formula for the cosine:
2 cos α cos β = cos ( α + β ) + cos ( α − β ) . {\displaystyle 2\cos \alpha \,\cos \beta =\cos(\alpha +\beta )+\cos(\alpha -\beta ).} For
n = 1 this results in the already known recurrence formula, just arranged differently, and with
n = 2 it forms the recurrence relation for all even or all odd indexed Chebyshev polynomials (depending on the parity of the lowest
m ) which implies the evenness or oddness of these polynomials. Three more useful formulas for evaluating Chebyshev polynomials can be concluded from this product expansion:
T 2 n ( x ) = 2 T n 2 ( x ) − T 0 ( x ) = 2 T n 2 ( x ) − 1 , T 2 n + 1 ( x ) = 2 T n + 1 ( x ) T n ( x ) − T 1 ( x ) = 2 T n + 1 ( x ) T n ( x ) − x , T 2 n − 1 ( x ) = 2 T n − 1 ( x ) T n ( x ) − T 1 ( x ) = 2 T n − 1 ( x ) T n ( x ) − x . {\displaystyle {\begin{aligned}T_{2n}(x)&=2\,T_{n}^{2}(x)-T_{0}(x)&&=2T_{n}^{2}(x)-1,\\T_{2n+1}(x)&=2\,T_{n+1}(x)\,T_{n}(x)-T_{1}(x)&&=2\,T_{n+1}(x)\,T_{n}(x)-x,\\T_{2n-1}(x)&=2\,T_{n-1}(x)\,T_{n}(x)-T_{1}(x)&&=2\,T_{n-1}(x)\,T_{n}(x)-x.\end{aligned}}} The polynomials of the second kind satisfy the similar relation:
T m ( x ) U n ( x ) = { 1 2 ( U m + n ( x ) + U n − m ( x ) ) , if n ≥ m − 1 , 1 2 ( U m + n ( x ) − U m − n − 2 ( x ) ) , if n ≤ m − 2. {\displaystyle T_{m}(x)\,U_{n}(x)={\begin{cases}{\frac {1}{2}}\left(U_{m+n}(x)+U_{n-m}(x)\right),&~{\text{ if }}~n\geq m-1,\\\\{\frac {1}{2}}\left(U_{m+n}(x)-U_{m-n-2}(x)\right),&~{\text{ if }}~n\leq m-2.\end{cases}}} (with the definition
U −1 ≡ 0 by convention ). They also satisfy:
U m ( x ) U n ( x ) = ∑ k = 0 n U m − n + 2 k ( x ) = ∑ p = m − n step 2 m + n U p ( x ) . {\displaystyle U_{m}(x)\,U_{n}(x)=\sum _{k=0}^{n}\,U_{m-n+2k}(x)=\sum _{\underset {\text{ step 2 }}{p=m-n}}^{m+n}U_{p}(x)~.} for
m ≥ n . For
n = 2 this recurrence reduces to:
U m + 2 ( x ) = U 2 ( x ) U m ( x ) − U m ( x ) − U m − 2 ( x ) = U m ( x ) ( U 2 ( x ) − 1 ) − U m − 2 ( x ) , {\displaystyle U_{m+2}(x)=U_{2}(x)\,U_{m}(x)-U_{m}(x)-U_{m-2}(x)=U_{m}(x)\,{\big (}U_{2}(x)-1{\big )}-U_{m-2}(x)~,} which establishes the evenness or oddness of the even or odd indexed Chebyshev polynomials of the second kind depending on whether
m starts with 2 or 3.
Composition and divisibility properties [ edit ] The trigonometric definitions of T n and U n imply the composition or nesting properties:[15]
T m n ( x ) = T m ( T n ( x ) ) , U m n − 1 ( x ) = U m − 1 ( T n ( x ) ) U n − 1 ( x ) . {\displaystyle {\begin{aligned}T_{mn}(x)&=T_{m}(T_{n}(x)),\\U_{mn-1}(x)&=U_{m-1}(T_{n}(x))U_{n-1}(x).\end{aligned}}} For
T mn the order of composition may be reversed, making the family of polynomial functions
T n a
commutative semigroup under composition.
Since T m (x ) is divisible by x if m is odd, it follows that T mn (x ) is divisible by T n (x ) if m is odd. Furthermore, U mn −1 (x ) is divisible by U n −1 (x ) , and in the case that m is even, divisible by T n (x )U n −1 (x ) .
Orthogonality [ edit ] Both Tn and Un form a sequence of orthogonal polynomials . The polynomials of the first kind Tn are orthogonal with respect to the weight:
1 1 − x 2 , {\displaystyle {\frac {1}{\sqrt {1-x^{2}}}},} on the interval
[−1, 1] , i.e. we have:
∫ − 1 1 T n ( x ) T m ( x ) d x 1 − x 2 = { 0 if n ≠ m , π if n = m = 0 , π 2 if n = m ≠ 0. {\displaystyle \int _{-1}^{1}T_{n}(x)\,T_{m}(x)\,{\frac {\mathrm {d} x}{\sqrt {1-x^{2}}}}={\begin{cases}0&~{\text{ if }}~n\neq m,\\[5mu]\pi &~{\text{ if }}~n=m=0,\\[5mu]{\frac {\pi }{2}}&~{\text{ if }}~n=m\neq 0.\end{cases}}} This can be proven by letting x = cos θ and using the defining identity T n (cos θ ) = cos(nθ ) .
Similarly, the polynomials of the second kind Un are orthogonal with respect to the weight:
1 − x 2 {\displaystyle {\sqrt {1-x^{2}}}} on the interval
[−1, 1] , i.e. we have:
∫ − 1 1 U n ( x ) U m ( x ) 1 − x 2 d x = { 0 if n ≠ m , π 2 if n = m . {\displaystyle \int _{-1}^{1}U_{n}(x)\,U_{m}(x)\,{\sqrt {1-x^{2}}}\,\mathrm {d} x={\begin{cases}0&~{\text{ if }}~n\neq m,\\[5mu]{\frac {\pi }{2}}&~{\text{ if }}~n=m.\end{cases}}} (The measure √1 − x 2 dx is, to within a normalizing constant, the Wigner semicircle distribution .)
These orthogonality properties follow from the fact that the Chebyshev polynomials solve the Chebyshev differential equations :
( 1 − x 2 ) T n ″ − x T n ′ + n 2 T n = 0 , ( 1 − x 2 ) U n ″ − 3 x U n ′ + n ( n + 2 ) U n = 0 , {\displaystyle {\begin{aligned}(1-x^{2})T_{n}''-xT_{n}'+n^{2}T_{n}&=0,\\[1ex](1-x^{2})U_{n}''-3xU_{n}'+n(n+2)U_{n}&=0,\end{aligned}}} which are
Sturm–Liouville differential equations . It is a general feature of such
differential equations that there is a distinguished orthonormal set of solutions. (Another way to define the Chebyshev polynomials is as the solutions to
those equations .)
The Tn also satisfy a discrete orthogonality condition:
∑ k = 0 N − 1 T i ( x k ) T j ( x k ) = { 0 if i ≠ j , N if i = j = 0 , N 2 if i = j ≠ 0 , {\displaystyle \sum _{k=0}^{N-1}{T_{i}(x_{k})\,T_{j}(x_{k})}={\begin{cases}0&~{\text{ if }}~i\neq j,\\[5mu]N&~{\text{ if }}~i=j=0,\\[5mu]{\frac {N}{2}}&~{\text{ if }}~i=j\neq 0,\end{cases}}} where
N is any integer greater than
max(i , j ) ,
[9] and the
x k are the
N Chebyshev nodes (see above) of
T N (x ):
x k = cos ( π 2 k + 1 2 N ) for k = 0 , 1 , … , N − 1. {\displaystyle x_{k}=\cos \left(\pi \,{\frac {2k+1}{2N}}\right)\quad ~{\text{ for }}~k=0,1,\dots ,N-1.} For the polynomials of the second kind and any integer N > i + j with the same Chebyshev nodes x k , there are similar sums:
∑ k = 0 N − 1 U i ( x k ) U j ( x k ) ( 1 − x k 2 ) = { 0 if i ≠ j , N 2 if i = j , {\displaystyle \sum _{k=0}^{N-1}{U_{i}(x_{k})\,U_{j}(x_{k})\left(1-x_{k}^{2}\right)}={\begin{cases}0&{\text{ if }}~i\neq j,\\[5mu]{\frac {N}{2}}&{\text{ if }}~i=j,\end{cases}}} and without the weight function:
∑ k = 0 N − 1 U i ( x k ) U j ( x k ) = { 0 if i ≢ j ( mod 2 ) , N ⋅ ( 1 + min { i , j } ) if i ≡ j ( mod 2 ) . {\displaystyle \sum _{k=0}^{N-1}{U_{i}(x_{k})\,U_{j}(x_{k})}={\begin{cases}0&~{\text{ if }}~i\not \equiv j{\pmod {2}},\\[5mu]N\cdot (1+\min\{i,j\})&~{\text{ if }}~i\equiv j{\pmod {2}}.\end{cases}}} For any integer N > i + j , based on the N zeros of U N (x ) :
y k = cos ( π k + 1 N + 1 ) for k = 0 , 1 , … , N − 1 , {\displaystyle y_{k}=\cos \left(\pi \,{\frac {k+1}{N+1}}\right)\quad ~{\text{ for }}~k=0,1,\dots ,N-1,} one can get the sum:
∑ k = 0 N − 1 U i ( y k ) U j ( y k ) ( 1 − y k 2 ) = { 0 if i ≠ j , N + 1 2 if i = j , {\displaystyle \sum _{k=0}^{N-1}{U_{i}(y_{k})\,U_{j}(y_{k})(1-y_{k}^{2})}={\begin{cases}0&~{\text{ if }}i\neq j,\\[5mu]{\frac {N+1}{2}}&~{\text{ if }}i=j,\end{cases}}} and again without the weight function:
∑ k = 0 N − 1 U i ( y k ) U j ( y k ) = { 0 if i ≢ j ( mod 2 ) , ( min { i , j } + 1 ) ( N − max { i , j } ) if i ≡ j ( mod 2 ) . {\displaystyle \sum _{k=0}^{N-1}{U_{i}(y_{k})\,U_{j}(y_{k})}={\begin{cases}0&~{\text{ if }}~i\not \equiv j{\pmod {2}},\\[5mu]{\bigl (}\min\{i,j\}+1{\bigr )}{\bigl (}N-\max\{i,j\}{\bigr )}&~{\text{ if }}~i\equiv j{\pmod {2}}.\end{cases}}} Minimal ∞ -norm [ edit ] For any given n ≥ 1 , among the polynomials of degree n with leading coefficient 1 (monic polynomials):
f ( x ) = 1 2 n − 1 T n ( x ) {\displaystyle f(x)={\frac {1}{\,2^{n-1}\,}}\,T_{n}(x)} is the one of which the maximal absolute value on the interval
[−1, 1] is minimal.
This maximal absolute value is:
1 2 n − 1 {\displaystyle {\frac {1}{2^{n-1}}}} and
|f (x ) | reaches this maximum exactly
n + 1 times at:
x = cos k π n for 0 ≤ k ≤ n . {\displaystyle x=\cos {\frac {k\pi }{n}}\quad {\text{for }}0\leq k\leq n.} Proof Let's assume that wn (x ) is a polynomial of degree n with leading coefficient 1 with maximal absolute value on the interval [−1, 1] less than 1 / 2n − 1 .
Define
f n ( x ) = 1 2 n − 1 T n ( x ) − w n ( x ) {\displaystyle f_{n}(x)={\frac {1}{\,2^{n-1}\,}}\,T_{n}(x)-w_{n}(x)} Because at extreme points of Tn we have
| w n ( x ) | < | 1 2 n − 1 T n ( x ) | f n ( x ) > 0 for x = cos 2 k π n where 0 ≤ 2 k ≤ n f n ( x ) < 0 for x = cos ( 2 k + 1 ) π n where 0 ≤ 2 k + 1 ≤ n {\displaystyle {\begin{aligned}|w_{n}(x)|&<\left|{\frac {1}{2^{n-1}}}T_{n}(x)\right|\\f_{n}(x)&>0\qquad {\text{ for }}~x=\cos {\frac {2k\pi }{n}}~&&{\text{ where }}0\leq 2k\leq n\\f_{n}(x)&<0\qquad {\text{ for }}~x=\cos {\frac {(2k+1)\pi }{n}}~&&{\text{ where }}0\leq 2k+1\leq n\end{aligned}}} From the intermediate value theorem , fn (x ) has at least n roots. However, this is impossible, as fn (x ) is a polynomial of degree n − 1 , so the fundamental theorem of algebra implies it has at most n − 1 roots.
By the equioscillation theorem , among all the polynomials of degree ≤ n , the polynomial f minimizes ‖ f ‖∞ on [−1, 1] if and only if there are n + 2 points −1 ≤ x 0 < x 1 < ⋯ < x n + 1 ≤ 1 such that | f (xi ) | = ‖ f ‖∞ .
Of course, the null polynomial on the interval [−1, 1] can be approximated by itself and minimizes the ∞ -norm.
Above, however, | f | reaches its maximum only n + 1 times because we are searching for the best polynomial of degree n ≥ 1 (therefore the theorem evoked previously cannot be used).
Chebyshev polynomials as special cases of more general polynomial families [ edit ] The Chebyshev polynomials are a special case of the ultraspherical or Gegenbauer polynomials C n ( λ ) ( x ) {\displaystyle C_{n}^{(\lambda )}(x)} , which themselves are a special case of the Jacobi polynomials P n ( α , β ) ( x ) {\displaystyle P_{n}^{(\alpha ,\beta )}(x)} :
T n ( x ) = n 2 lim q → 0 1 q C n ( q ) ( x ) if n ≥ 1 , = 1 ( n − 1 2 n ) P n ( − 1 2 , − 1 2 ) ( x ) = 2 2 n ( 2 n n ) P n ( − 1 2 , − 1 2 ) ( x ) , U n ( x ) = C n ( 1 ) ( x ) = n + 1 ( n + 1 2 n ) P n ( 1 2 , 1 2 ) ( x ) = 2 2 n + 1 ( 2 n + 2 n + 1 ) P n ( 1 2 , 1 2 ) ( x ) . {\displaystyle {\begin{aligned}T_{n}(x)&={\frac {n}{2}}\lim _{q\to 0}{\frac {1}{q}}\,C_{n}^{(q)}(x)\qquad ~{\text{ if }}~n\geq 1,\\&={\frac {1}{\binom {n-{\frac {1}{2}}}{n}}}P_{n}^{\left(-{\frac {1}{2}},-{\frac {1}{2}}\right)}(x)={\frac {2^{2n}}{\binom {2n}{n}}}P_{n}^{\left(-{\frac {1}{2}},-{\frac {1}{2}}\right)}(x)~,\\[2ex]U_{n}(x)&=C_{n}^{(1)}(x)\\&={\frac {n+1}{\binom {n+{\frac {1}{2}}}{n}}}P_{n}^{\left({\frac {1}{2}},{\frac {1}{2}}\right)}(x)={\frac {2^{2n+1}}{\binom {2n+2}{n+1}}}P_{n}^{\left({\frac {1}{2}},{\frac {1}{2}}\right)}(x)~.\end{aligned}}} Chebyshev polynomials are also a special case of Dickson polynomials :
D n ( 2 x α , α 2 ) = 2 α n T n ( x ) {\displaystyle D_{n}(2x\alpha ,\alpha ^{2})=2\alpha ^{n}T_{n}(x)\,} E n ( 2 x α , α 2 ) = α n U n ( x ) . {\displaystyle E_{n}(2x\alpha ,\alpha ^{2})=\alpha ^{n}U_{n}(x).\,} In particular, when
α = 1 2 {\displaystyle \alpha ={\tfrac {1}{2}}} , they are related by
D n ( x , 1 4 ) = 2 1 − n T n ( x ) {\displaystyle D_{n}(x,{\tfrac {1}{4}})=2^{1-n}T_{n}(x)} and
E n ( x , 1 4 ) = 2 − n U n ( x ) {\displaystyle E_{n}(x,{\tfrac {1}{4}})=2^{-n}U_{n}(x)} .
Other properties [ edit ] The curves given by y = T n (x ) , or equivalently, by the parametric equations y = T n (cos θ ) = cos nθ , x = cos θ , are a special case of Lissajous curves with frequency ratio equal to n .
Similar to the formula:
T n ( cos θ ) = cos ( n θ ) , {\displaystyle T_{n}(\cos \theta )=\cos(n\theta ),} we have the analogous formula:
T 2 n + 1 ( sin θ ) = ( − 1 ) n sin ( ( 2 n + 1 ) θ ) . {\displaystyle T_{2n+1}(\sin \theta )=(-1)^{n}\sin \left(\left(2n+1\right)\theta \right).} For x ≠ 0 :
T n ( x + x − 1 2 ) = x n + x − n 2 {\displaystyle T_{n}\!\left({\frac {x+x^{-1}}{2}}\right)={\frac {x^{n}+x^{-n}}{2}}} and:
x n = T n ( x + x − 1 2 ) + x − x − 1 2 U n − 1 ( x + x − 1 2 ) , {\displaystyle x^{n}=T_{n}\!\left({\frac {x+x^{-1}}{2}}\right)+{\frac {x-x^{-1}}{2}}\ U_{n-1}\!\left({\frac {x+x^{-1}}{2}}\right),} which follows from the fact that this holds by definition for
x = eiθ .
Examples [ edit ] First kind [ edit ] The first few Chebyshev polynomials of the first kind in the domain −1 < x < 1 : The flat T 0 , T 1 , T 2 , T 3 , T 4 and T 5 . The first few Chebyshev polynomials of the first kind are OEIS : A028297
T 0 ( x ) = 1 T 1 ( x ) = x T 2 ( x ) = 2 x 2 − 1 T 3 ( x ) = 4 x 3 − 3 x T 4 ( x ) = 8 x 4 − 8 x 2 + 1 T 5 ( x ) = 16 x 5 − 20 x 3 + 5 x T 6 ( x ) = 32 x 6 − 48 x 4 + 18 x 2 − 1 T 7 ( x ) = 64 x 7 − 112 x 5 + 56 x 3 − 7 x T 8 ( x ) = 128 x 8 − 256 x 6 + 160 x 4 − 32 x 2 + 1 T 9 ( x ) = 256 x 9 − 576 x 7 + 432 x 5 − 120 x 3 + 9 x T 10 ( x ) = 512 x 10 − 1280 x 8 + 1120 x 6 − 400 x 4 + 50 x 2 − 1 {\displaystyle {\begin{aligned}T_{0}(x)&=1\\T_{1}(x)&=x\\T_{2}(x)&=2x^{2}-1\\T_{3}(x)&=4x^{3}-3x\\T_{4}(x)&=8x^{4}-8x^{2}+1\\T_{5}(x)&=16x^{5}-20x^{3}+5x\\T_{6}(x)&=32x^{6}-48x^{4}+18x^{2}-1\\T_{7}(x)&=64x^{7}-112x^{5}+56x^{3}-7x\\T_{8}(x)&=128x^{8}-256x^{6}+160x^{4}-32x^{2}+1\\T_{9}(x)&=256x^{9}-576x^{7}+432x^{5}-120x^{3}+9x\\T_{10}(x)&=512x^{10}-1280x^{8}+1120x^{6}-400x^{4}+50x^{2}-1\end{aligned}}} Second kind [ edit ] The first few Chebyshev polynomials of the second kind in the domain −1 < x < 1 : The flat U 0 , U 1 , U 2 , U 3 , U 4 and U 5 . Although not visible in the image, U n (1) = n + 1 and U n (−1) = (n + 1)(−1)n . The first few Chebyshev polynomials of the second kind are OEIS : A053117
U 0 ( x ) = 1 U 1 ( x ) = 2 x U 2 ( x ) = 4 x 2 − 1 U 3 ( x ) = 8 x 3 − 4 x U 4 ( x ) = 16 x 4 − 12 x 2 + 1 U 5 ( x ) = 32 x 5 − 32 x 3 + 6 x U 6 ( x ) = 64 x 6 − 80 x 4 + 24 x 2 − 1 U 7 ( x ) = 128 x 7 − 192 x 5 + 80 x 3 − 8 x U 8 ( x ) = 256 x 8 − 448 x 6 + 240 x 4 − 40 x 2 + 1 U 9 ( x ) = 512 x 9 − 1024 x 7 + 672 x 5 − 160 x 3 + 10 x U 10 ( x ) = 1024 x 10 − 2304 x 8 + 1792 x 6 − 560 x 4 + 60 x 2 − 1 {\displaystyle {\begin{aligned}U_{0}(x)&=1\\U_{1}(x)&=2x\\U_{2}(x)&=4x^{2}-1\\U_{3}(x)&=8x^{3}-4x\\U_{4}(x)&=16x^{4}-12x^{2}+1\\U_{5}(x)&=32x^{5}-32x^{3}+6x\\U_{6}(x)&=64x^{6}-80x^{4}+24x^{2}-1\\U_{7}(x)&=128x^{7}-192x^{5}+80x^{3}-8x\\U_{8}(x)&=256x^{8}-448x^{6}+240x^{4}-40x^{2}+1\\U_{9}(x)&=512x^{9}-1024x^{7}+672x^{5}-160x^{3}+10x\\U_{10}(x)&=1024x^{10}-2304x^{8}+1792x^{6}-560x^{4}+60x^{2}-1\end{aligned}}} As a basis set [ edit ] The non-smooth function (top) y = −x 3 H (−x ) , where H is the Heaviside step function , and (bottom) the 5th partial sum of its Chebyshev expansion. The 7th sum is indistinguishable from the original function at the resolution of the graph. In the appropriate Sobolev space , the set of Chebyshev polynomials form an orthonormal basis , so that a function in the same space can, on −1 ≤ x ≤ 1 , be expressed via the expansion:[16]
f ( x ) = ∑ n = 0 ∞ a n T n ( x ) . {\displaystyle f(x)=\sum _{n=0}^{\infty }a_{n}T_{n}(x).} Furthermore, as mentioned previously, the Chebyshev polynomials form an orthogonal basis which (among other things) implies that the coefficients a n can be determined easily through the application of an inner product . This sum is called a Chebyshev series or a Chebyshev expansion .
Since a Chebyshev series is related to a Fourier cosine series through a change of variables, all of the theorems, identities, etc. that apply to Fourier series have a Chebyshev counterpart.[16] These attributes include:
The Chebyshev polynomials form a complete orthogonal system. The Chebyshev series converges to f (x ) if the function is piecewise smooth and continuous . The smoothness requirement can be relaxed in most cases – as long as there are a finite number of discontinuities in f (x ) and its derivatives. At a discontinuity, the series will converge to the average of the right and left limits. The abundance of the theorems and identities inherited from Fourier series make the Chebyshev polynomials important tools in numeric analysis ; for example they are the most popular general purpose basis functions used in the spectral method ,[16] often in favor of trigonometric series due to generally faster convergence for continuous functions (Gibbs' phenomenon is still a problem).
Example 1 [ edit ] Consider the Chebyshev expansion of log(1 + x ) . One can express:
log ( 1 + x ) = ∑ n = 0 ∞ a n T n ( x ) . {\displaystyle \log(1+x)=\sum _{n=0}^{\infty }a_{n}T_{n}(x)~.} One can find the coefficients an either through the application of an inner product or by the discrete orthogonality condition. For the inner product:
∫ − 1 + 1 T m ( x ) log ( 1 + x ) 1 − x 2 d x = ∑ n = 0 ∞ a n ∫ − 1 + 1 T m ( x ) T n ( x ) 1 − x 2 d x , {\displaystyle \int _{-1}^{+1}\,{\frac {T_{m}(x)\,\log(1+x)}{\sqrt {1-x^{2}}}}\,\mathrm {d} x=\sum _{n=0}^{\infty }a_{n}\int _{-1}^{+1}{\frac {T_{m}(x)\,T_{n}(x)}{\sqrt {1-x^{2}}}}\,\mathrm {d} x,} which gives:
a n = { − log 2 for n = 0 , − 2 ( − 1 ) n n for n > 0. {\displaystyle a_{n}={\begin{cases}-\log 2&{\text{ for }}~n=0,\\{\frac {-2(-1)^{n}}{n}}&{\text{ for }}~n>0.\end{cases}}} Alternatively, when the inner product of the function being approximated cannot be evaluated, the discrete orthogonality condition gives an often useful result for approximate coefficients:
a n ≈ 2 − δ 0 n N ∑ k = 0 N − 1 T n ( x k ) log ( 1 + x k ) , {\displaystyle a_{n}\approx {\frac {\,2-\delta _{0n}\,}{N}}\,\sum _{k=0}^{N-1}T_{n}(x_{k})\,\log(1+x_{k}),} where
δij is the
Kronecker delta function and the
xk are the
N Gauss–Chebyshev zeros of
T N (x ):
x k = cos ( π ( k + 1 2 ) N ) . {\displaystyle x_{k}=\cos \left({\frac {\pi \left(k+{\tfrac {1}{2}}\right)}{N}}\right).} For any
N , these approximate coefficients provide an exact approximation to the function at
xk with a controlled error between those points. The exact coefficients are obtained with
N = ∞, thus representing the function exactly at all points in
[−1,1] . The rate of convergence depends on the function and its smoothness.
This allows us to compute the approximate coefficients an very efficiently through the discrete cosine transform :
a n ≈ 2 − δ 0 n N ∑ k = 0 N − 1 cos ( n π ( k + 1 2 ) N ) log ( 1 + x k ) . {\displaystyle a_{n}\approx {\frac {2-\delta _{0n}}{N}}\sum _{k=0}^{N-1}\cos \left({\frac {n\pi \left(\,k+{\tfrac {1}{2}}\right)}{N}}\right)\log(1+x_{k}).} Example 2 [ edit ] To provide another example:
( 1 − x 2 ) α = − 1 π Γ ( 1 2 + α ) Γ ( α + 1 ) + 2 1 − 2 α ∑ n = 0 ( − 1 ) n ( 2 α α − n ) T 2 n ( x ) = 2 − 2 α ∑ n = 0 ( − 1 ) n ( 2 α + 1 α − n ) U 2 n ( x ) . {\displaystyle {\begin{aligned}\left(1-x^{2}\right)^{\alpha }&=-{\frac {1}{\sqrt {\pi }}}\,{\frac {\Gamma \left({\tfrac {1}{2}}+\alpha \right)}{\Gamma (\alpha +1)}}+2^{1-2\alpha }\,\sum _{n=0}\left(-1\right)^{n}\,{2\alpha \choose \alpha -n}\,T_{2n}(x)\\[1ex]&=2^{-2\alpha }\,\sum _{n=0}\left(-1\right)^{n}\,{2\alpha +1 \choose \alpha -n}\,U_{2n}(x).\end{aligned}}} Partial sums [ edit ] The partial sums of:
f ( x ) = ∑ n = 0 ∞ a n T n ( x ) {\displaystyle f(x)=\sum _{n=0}^{\infty }a_{n}T_{n}(x)} are very useful in the
approximation of various functions and in the solution of
differential equations (see
spectral method ). Two common methods for determining the coefficients
an are through the use of the
inner product as in
Galerkin's method and through the use of
collocation which is related to
interpolation .
As an interpolant, the N coefficients of the (N − 1) st partial sum are usually obtained on the Chebyshev–Gauss–Lobatto[17] points (or Lobatto grid), which results in minimum error and avoids Runge's phenomenon associated with a uniform grid. This collection of points corresponds to the extrema of the highest order polynomial in the sum, plus the endpoints and is given by:
x k = − cos ( k π N − 1 ) ; k = 0 , 1 , … , N − 1. {\displaystyle x_{k}=-\cos \left({\frac {k\pi }{N-1}}\right);\qquad k=0,1,\dots ,N-1.} Polynomial in Chebyshev form [ edit ] An arbitrary polynomial of degree N can be written in terms of the Chebyshev polynomials of the first kind.[9] Such a polynomial p (x ) is of the form:
p ( x ) = ∑ n = 0 N a n T n ( x ) . {\displaystyle p(x)=\sum _{n=0}^{N}a_{n}T_{n}(x).} Polynomials in Chebyshev form can be evaluated using the Clenshaw algorithm .
Families of polynomials related to Chebyshev polynomials [ edit ] Polynomials denoted C n ( x ) {\displaystyle C_{n}(x)} and S n ( x ) {\displaystyle S_{n}(x)} closely related to Chebyshev polynomials are sometimes used. They are defined by:[18]