Hahn–Banach theorem
The Hahn–Banach theorem is a central tool in functional analysis. It allows the extension of bounded linear functionals defined on a vector subspace of some vector space to the whole space, and it also shows that there are "enough" continuous linear functionals defined on every normed vector space to make the study of the dual space "interesting". Another version of the Hahn–Banach theorem is known as the Hahn–Banach separation theorem or the hyperplane separation theorem, and has numerous uses in convex geometry.
History
[edit]The theorem is named for the mathematicians Hans Hahn and Stefan Banach, who proved it independently in the late 1920s. The special case of the theorem for the space of continuous functions on an interval was proved earlier (in 1912) by Eduard Helly,[1] and a more general extension theorem, the M. Riesz extension theorem, from which the Hahn–Banach theorem can be derived, was proved in 1923 by Marcel Riesz.[2]
The first Hahn–Banach theorem was proved by Eduard Helly in 1912 who showed that certain linear functionals defined on a subspace of a certain type of normed space () had an extension of the same norm. Helly did this through the technique of first proving that a one-dimensional extension exists (where the linear functional has its domain extended by one dimension) and then using induction. In 1927, Hahn defined general Banach spaces and used Helly's technique to prove a norm-preserving version of Hahn–Banach theorem for Banach spaces (where a bounded linear functional on a subspace has a bounded linear extension of the same norm to the whole space). In 1929, Banach, who was unaware of Hahn's result, generalized it by replacing the norm-preserving version with the dominated extension version that uses sublinear functions. Whereas Helly's proof used mathematical induction, Hahn and Banach both used transfinite induction.[3]
The Hahn–Banach theorem arose from attempts to solve infinite systems of linear equations. This is needed to solve problems such as the moment problem, whereby given all the potential moments of a function one must determine if a function having these moments exists, and, if so, find it in terms of those moments. Another such problem is the Fourier cosine series problem, whereby given all the potential Fourier cosine coefficients one must determine if a function having those coefficients exists, and, again, find it if so.
Riesz and Helly solved the problem for certain classes of spaces (such as and ) where they discovered that the existence of a solution was equivalent to the existence and continuity of certain linear functionals. In effect, they needed to solve the following problem:[3]
- (The vector problem) Given a collection of bounded linear functionals on a normed space and a collection of scalars determine if there is an such that for all
If happens to be a reflexive space then to solve the vector problem, it suffices to solve the following dual problem:[3]
- (The functional problem) Given a collection of vectors in a normed space and a collection of scalars determine if there is a bounded linear functional on such that for all
Riesz went on to define space () in 1910 and the spaces in 1913. While investigating these spaces he proved a special case of the Hahn–Banach theorem. Helly also proved a special case of the Hahn–Banach theorem in 1912. In 1910, Riesz solved the functional problem for some specific spaces and in 1912, Helly solved it for a more general class of spaces. It wasn't until 1932 that Banach, in one of the first important applications of the Hahn–Banach theorem, solved the general functional problem. The following theorem states the general functional problem and characterizes its solution.[3]
Theorem[3] (The functional problem) — Let be vectors in a real or complex normed space and let be scalars also indexed by
There exists a continuous linear functional on such that for all if and only if there exists a such that for any choice of scalars where all but finitely many are the following holds:
The Hahn–Banach theorem can be deduced from the above theorem.[3] If is reflexive then this theorem solves the vector problem.
Hahn–Banach theorem
[edit]A real-valued function defined on a subset of is said to be dominated (above) by a function if for every Hence the reason why the following version of the Hahn–Banach theorem is called the dominated extension theorem.
Hahn–Banach dominated extension theorem (for real linear functionals)[4][5][6] — If is a sublinear function (such as a norm or seminorm for example) defined on a real vector space then any linear functional defined on a vector subspace of that is dominated above by has at least one linear extension to all of that is also dominated above by
Explicitly, if is a sublinear function, which by definition means that it satisfies and if is a linear functional defined on a vector subspace of such that then there exists a linear functional such that Moreover, if is a seminorm then necessarily holds for all
The theorem remains true if the requirements on are relaxed to require only that be a convex function:[7][8] A function is convex and satisfies if and only if for all vectors and all non-negative real such that Every sublinear function is a convex function. On the other hand, if is convex with then the function defined by is positively homogeneous (because for all and one has ), hence, being convex, it is sublinear. It is also bounded above by and satisfies for every linear functional So the extension of the Hahn–Banach theorem to convex functionals does not have a much larger content than the classical one stated for sublinear functionals.
If is linear then if and only if[4] which is the (equivalent) conclusion that some authors[4] write instead of It follows that if is also symmetric, meaning that holds for all then if and only Every norm is a seminorm and both are symmetric balanced sublinear functions. A sublinear function is a seminorm if and only if it is a balanced function. On a real vector space (although not on a complex vector space), a sublinear function is a seminorm if and only if it is symmetric. The identity function on is an example of a sublinear function that is not a seminorm.
For complex or real vector spaces
[edit]The dominated extension theorem for real linear functionals implies the following alternative statement of the Hahn–Banach theorem that can be applied to linear functionals on real or complex vector spaces.
Hahn–Banach theorem[3][9] — Suppose a seminorm on a vector space over the field which is either or If is a linear functional on a vector subspace such that then there exists a linear functional such that
The theorem remains true if the requirements on are relaxed to require only that for all and all scalars and satisfying [8] This condition holds if and only if is a convex and balanced function satisfying or equivalently, if and only if it is convex, satisfies and for all and all unit length scalars
A complex-valued functional is said to be dominated by if for all in the domain of With this terminology, the above statements of the Hahn–Banach theorem can be restated more succinctly:
- Hahn–Banach dominated extension theorem: If is a seminorm defined on a real or complex vector space then every dominated linear functional defined on a vector subspace of has a dominated linear extension to all of In the case where is a real vector space and is merely a convex or sublinear function, this conclusion will remain true if both instances of "dominated" (meaning ) are weakened to instead mean "dominated above" (meaning ).[7][8]
Proof
The following observations allow the Hahn–Banach theorem for real vector spaces to be applied to (complex-valued) linear functionals on complex vector spaces.
Every linear functional on a complex vector space is completely determined by its real part through the formula[6][proof 1] and moreover, if is a norm on then their dual norms are equal: [10] In particular, a linear functional on extends another one defined on if and only if their real parts are equal on (in other words, a linear functional extends if and only if extends ). The real part of a linear functional on is always a real-linear functional (meaning that it is linear when is considered as a real vector space) and if is a real-linear functional on a complex vector space then defines the unique linear functional on whose real part is
If is a linear functional on a (complex or real) vector space and if is a seminorm then[6][proof 2] Stated in simpler language, a linear functional is dominated by a seminorm if and only if its real part is dominated above by
Suppose is a seminorm on a complex vector space and let be a linear functional defined on a vector subspace of that satisfies on Consider as a real vector space and apply the Hahn–Banach theorem for real vector spaces to the real-linear functional to obtain a real-linear extension that is also dominated above by so that it satisfies on and on The map defined by is a linear functional on that extends (because their real parts agree on ) and satisfies on (because and is a seminorm).
The proof above shows that when is a seminorm then there is a one-to-one correspondence between dominated linear extensions of and dominated real-linear extensions of the proof even gives a formula for explicitly constructing a linear extension of from any given real-linear extension of its real part.
Continuity
A linear functional on a topological vector space is continuous if and only if this is true of its real part if the domain is a normed space then (where one side is infinite if and only if the other side is infinite).[10] Assume is a topological vector space and is sublinear function. If is a continuous sublinear function that dominates a linear functional then is necessarily continuous.[6] Moreover, a linear functional is continuous if and only if its absolute value (which is a seminorm that dominates ) is continuous.[6] In particular, a linear functional is continuous if and only if it is dominated by some continuous sublinear function.
Proof
[edit]The Hahn–Banach theorem for real vector spaces ultimately follows from Helly's initial result for the special case where the linear functional is extended from to a larger vector space in which has codimension [3]
Lemma[6] (One–dimensional dominated extension theorem) — Let be a sublinear function on a real vector space let a linear functional on a proper vector subspace such that on (meaning for all ), and let be a vector not in (so ). There exists a linear extension of such that on
Given any real number the map defined by is always a linear extension of to [note 1] but it might not satisfy It will be shown that can always be chosen so as to guarantee that which will complete the proof.
If then which implies So define where are real numbers. To guarantee it suffices that (in fact, this is also necessary[note 2]) because then satisfies "the decisive inequality"[6]
To see that follows,[note 3] assume and substitute in for both and to obtain If (respectively, if ) then the right (respectively, the left) hand side equals so that multiplying by gives
This lemma remains true if is merely a convex function instead of a sublinear function.[7][8]
Proof |
---|
Assume that is convex, which means that for all and Let and be as in the lemma's statement. Given any and any positive real the positive real numbers and sum to so that the convexity of on guarantees and hence thus proving that which after multiplying both sides by becomes This implies that the values defined by are real numbers that satisfy As in the above proof of the one–dimensional dominated extension theorem above, for any real define by It can be verified that if then where follows from when (respectively, follows from when ). |
The lemma above is the key step in deducing the dominated extension theorem from Zorn's lemma.
The set of all possible dominated linear extensions of are partially ordered by extension of each other, so there is a maximal extension By the codimension-1 result, if is not defined on all of then it can be further extended. Thus must be defined everywhere, as claimed.
When has countable codimension, then using induction and the lemma completes the proof of the Hahn–Banach theorem. The standard proof of the general case uses Zorn's lemma although the strictly weaker ultrafilter lemma[11] (which is equivalent to the compactness theorem and to the Boolean prime ideal theorem) may be used instead. Hahn–Banach can also be proved using Tychonoff's theorem for compact Hausdorff spaces[12] (which is also equivalent to the ultrafilter lemma)
The Mizar project has completely formalized and automatically checked the proof of the Hahn–Banach theorem in the HAHNBAN file.[13]
Continuous extension theorem
[edit]The Hahn–Banach theorem can be used to guarantee the existence of continuous linear extensions of continuous linear functionals.
Hahn–Banach continuous extension theorem[14] — Every continuous linear functional defined on a vector subspace of a (real or complex) locally convex topological vector space has a continuous linear extension to all of If in addition is a normed space, then this extension can be chosen so that its dual norm is equal to that of
In category-theoretic terms, the underlying field of the vector space is an injective object in the category of locally convex vector spaces.
On a normed (or seminormed) space, a linear extension of a bounded linear functional is said to be norm-preserving if it has the same dual norm as the original functional: Because of this terminology, the second part of the above theorem is sometimes referred to as the "norm-preserving" version of the Hahn–Banach theorem.[15] Explicitly:
Norm-preserving Hahn–Banach continuous extension theorem[15] — Every continuous linear functional defined on a vector subspace of a (real or complex) normed space has a continuous linear extension to all of that satisfies
Proof of the continuous extension theorem
[edit]The following observations allow the continuous extension theorem to be deduced from the Hahn–Banach theorem.[16]
The absolute value of a linear functional is always a seminorm. A linear functional on a topological vector space is continuous if and only if its absolute value is continuous, which happens if and only if there exists a continuous seminorm on such that on the domain of [17] If is a locally convex space then this statement remains true when the linear functional is defined on a proper vector subspace of
Let be a continuous linear functional defined on a vector subspace of a locally convex topological vector space Because is locally convex, there exists a continuous seminorm on that dominates (meaning that for all ). By the Hahn–Banach theorem, there exists a linear extension of to call it that satisfies on This linear functional is continuous since and is a continuous seminorm.
Proof for normed spaces
A linear functional on a normed space is continuous if and only if it is bounded, which means that its dual norm is finite, in which case holds for every point in its domain. Moreover, if is such that for all in the functional's domain, then necessarily If is a linear extension of a linear functional then their dual norms always satisfy [proof 3] so that equality is equivalent to which holds if and only if for every point in the extension's domain. This can be restated in terms of the function defined by which is always a seminorm:[note 4]
- A linear extension of a bounded linear functional is norm-preserving if and only if the extension is dominated by the seminorm
Applying the Hahn–Banach theorem to with this seminorm thus produces a dominated linear extension whose norm is (necessarily) equal to that of which proves the theorem:
Let be a continuous linear functional defined on a vector subspace of a normed space Then the function defined by is a seminorm on that dominates meaning that holds for every By the Hahn–Banach theorem, there exists a linear functional on that extends (which guarantees ) and that is also dominated by meaning that for every The fact that is a real number such that for every guarantees Since is finite, the linear functional is bounded and thus continuous.
Non-locally convex spaces
[edit]The continuous extension theorem might fail if the topological vector space (TVS) is not locally convex. For example, for the Lebesgue space is a complete metrizable TVS (an F-space) that is not locally convex (in fact, its only convex open subsets are itself and the empty set) and the only continuous linear functional on is the constant function (Rudin 1991, §1.47). Since is Hausdorff, every finite-dimensional vector subspace is linearly homeomorphic to Euclidean space or (by F. Riesz's theorem) and so every non-zero linear functional on is continuous but none has a continuous linear extension to all of However, it is possible for a TVS to not be locally convex but nevertheless have enough continuous linear functionals that its continuous dual space separates points; for such a TVS, a continuous linear functional defined on a vector subspace might have a continuous linear extension to the whole space.
If the TVS is not locally convex then there might not exist any continuous seminorm defined on (not just on ) that dominates in which case the Hahn–Banach theorem can not be applied as it was in the above proof of the continuous extension theorem. However, the proof's argument can be generalized to give a characterization of when a continuous linear functional has a continuous linear extension: If is any TVS (not necessarily locally convex), then a continuous linear functional defined on a vector subspace has a continuous linear extension to all of if and only if there exists some continuous seminorm on that dominates Specifically, if given a continuous linear extension then is a continuous seminorm on that dominates and conversely, if given a continuous seminorm on that dominates then any dominated linear extension of to (the existence of which is guaranteed by the Hahn–Banach theorem) will be a continuous linear extension.
Geometric Hahn–Banach (the Hahn–Banach separation theorems)
[edit]The key element of the Hahn–Banach theorem is fundamentally a result about the separation of two convex sets: and This sort of argument appears widely in convex geometry,[18] optimization theory, and economics. Lemmas to this end derived from the original Hahn–Banach theorem are known as the Hahn–Banach separation theorems.[19][20] They are generalizations of the hyperplane separation theorem, which states that two disjoint nonempty convex subsets of a finite-dimensional space can be separated by some affine hyperplane, which is a fiber (level set) of the form where is a non-zero linear functional and is a scalar.
Theorem[19] — Let and be non-empty convex subsets of a real locally convex topological vector space If and then there exists a continuous linear functional on such that and for all (such an is necessarily non-zero).
When the convex sets have additional properties, such as being open or compact for example, then the conclusion can be substantially strengthened:
Theorem[3][21] — Let and be convex non-empty disjoint subsets of a real topological vector space
- If is open then and are separated by a closed hyperplane. Explicitly, this means that there exists a continuous linear map and such that for all If both and are open then the right-hand side may be taken strict as well.
- If is locally convex, is compact, and closed, then and are strictly separated: there exists a continuous linear map and such that for all
If is complex (rather than real) then the same claims hold, but for the real part of
Then following important corollary is known as the Geometric Hahn–Banach theorem or Mazur's theorem (also known as Ascoli–Mazur theorem[22]). It follows from the first bullet above and the convexity of
Theorem (Mazur)[23] — Let be a vector subspace of the topological vector space and suppose is a non-empty convex open subset of with Then there is a closed hyperplane (codimension-1 vector subspace) that contains but remains disjoint from
Mazur's theorem clarifies that vector subspaces (even those that are not closed) can be characterized by linear functionals.
Corollary[24] (Separation of a subspace and an open convex set) — Let be a vector subspace of a locally convex topological vector space and be a non-empty open convex subset disjoint from Then there exists a continuous linear functional on such that for all and on
Supporting hyperplanes
[edit]Since points are trivially convex, geometric Hahn–Banach implies that functionals can detect the boundary of a set. In particular, let be a real topological vector space and be convex with If then there is a functional that is vanishing at but supported on the interior of [19]
Call a normed space smooth if at each point in its unit ball there exists a unique closed hyperplane to the unit ball at Köthe showed in 1983 that a normed space is smooth at a point if and only if the norm is Gateaux differentiable at that point.[3]
Balanced or disked neighborhoods
[edit]Let be a convex balanced neighborhood of the origin in a locally convex topological vector space and suppose is not an element of Then there exists a continuous linear functional on such that[3]
Applications
[edit]The Hahn–Banach theorem is the first sign of an important philosophy in functional analysis: to understand a space, one should understand its continuous functionals.
For example, linear subspaces are characterized by functionals: if X is a normed vector space with linear subspace M (not necessarily closed) and if is an element of X not in the closure of M, then there exists a continuous linear map with for all and (To see this, note that is a sublinear function.) Moreover, if is an element of X, then there exists a continuous linear map such that and This implies that the natural injection from a normed space X into its double dual is isometric.
That last result also suggests that the Hahn–Banach theorem can often be used to locate a "nicer" topology in which to work. For example, many results in functional analysis assume that a space is Hausdorff or locally convex. However, suppose X is a topological vector space, not necessarily Hausdorff or locally convex, but with a nonempty, proper, convex, open set M. Then geometric Hahn–Banach implies that there is a hyperplane separating M from any other point. In particular, there must exist a nonzero functional on X — that is, the continuous dual space is non-trivial.[3][25] Considering X with the weak topology induced by then X becomes locally convex; by the second bullet of geometric Hahn–Banach, the weak topology on this new space separates points. Thus X with this weak topology becomes Hausdorff. This sometimes allows some results from locally convex topological vector spaces to be applied to non-Hausdorff and non-locally convex spaces.
Partial differential equations
[edit]The Hahn–Banach theorem is often useful when one wishes to apply the method of a priori estimates. Suppose that we wish to solve the linear differential equation for with given in some Banach space X. If we have control on the size of in terms of and we can think of as a bounded linear functional on some suitable space of test functions then we can view as a linear functional by adjunction: At first, this functional is only defined on the image of but using the Hahn–Banach theorem, we can try to extend it to the entire codomain X. The resulting functional is often defined to be a weak solution to the equation.
Characterizing reflexive Banach spaces
[edit]Theorem[26] — A real Banach space is reflexive if and only if every pair of non-empty disjoint closed convex subsets, one of which is bounded, can be strictly separated by a hyperplane.
Example from Fredholm theory
[edit]To illustrate an actual application of the Hahn–Banach theorem, we will now prove a result that follows almost entirely from the Hahn–Banach theorem.
Proposition — Suppose is a Hausdorff locally convex TVS over the field and