Open mapping theorem (complex analysis)

In complex analysis, the open mapping theorem states that if is a domain of the complex plane and is a non-constant holomorphic function, then is an open map (i.e. it sends open subsets of to open subsets of , and we have invariance of domain.).

The open mapping theorem points to the sharp difference between holomorphy and real-differentiability. On the real line, for example, the differentiable function is not an open map, as the image of the open interval is the half-open interval .

The theorem for example implies that a non-constant holomorphic function cannot map an open disk onto a portion of any line embedded in the complex plane. Images of holomorphic functions can be of real dimension zero (if constant) or two (if non-constant) but never of dimension 1.

Proof

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Black dots represent zeros of . Black annuli represent poles. The boundary of the open set is given by the dashed line. Note that all poles are exterior to the open set. The smaller red disk is , centered at .

Assume is a non-constant holomorphic function and is a domain of the complex plane. We have to show that every point in is an interior point of , i.e. that every point in has a neighborhood (open disk) which is also in .

Consider an arbitrary in . Then there exists a point in such that . Since is open, we can find such that the closed disk around with radius is fully contained in . Consider the function . Note that is a root of the function.

We know that is non-constant and holomorphic. The roots of are isolated by the identity theorem, and by further decreasing the radius of the disk , we can assure that has only a single root in (although this single root may have multiplicity greater than 1).

The boundary of is a circle and hence a compact set, on which Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "http://localhost:6011/en.wikipedia.org/v1/":): {\displaystyle |g(z)|} is a positive continuous function, so the extreme value theorem guarantees the existence of a positive minimum , that is, is the minimum of for on the boundary of and .

Denote by the open disk around with radius . By Rouché's theorem, the function will have the same number of roots (counted with multiplicity) in as for any in . This is because , and for on the boundary of , . Thus, for every in , there exists at least one in such that . This means that the disk is contained in .

The image of the ball , is a subset of the image of , . Thus is an interior point of . Since was arbitrary in we know that is open. Since was arbitrary, the function is open.

Applications

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See also

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References

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  • Rudin, Walter (1966), Real & Complex Analysis, McGraw-Hill, ISBN 0-07-054234-1