1885 Iowa gubernatorial election

1885 Iowa gubernatorial election

← 1883 November 3, 1885 1887 →
 
Nominee William Larrabee Charles E. Whiting
Party Republican Democratic
Popular vote 175,605 168,584
Percentage 50.76% 48.73%

County results
Larrabee:      40-50%      50-60%      60-70%      70-80%
Whiting:      40-50%      50-60%      60-70%

Governor before election

Buren R. Sherman
Republican

Elected Governor

William Larrabee
Republican

The 1885 Iowa gubernatorial election was held on November 3, 1885. Republican nominee William Larrabee defeated Democratic nominee Charles E. Whiting with 50.76% of the vote.

General election

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Candidates

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Major party candidates

  • William Larrabee, Republican
  • Charles E. Whiting, Democratic

Other candidates

  • James Michelwait, Prohibition
  • Elias Doty, Greenback

Results

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1885 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican William Larrabee 175,605 50.76%
Democratic Charles E. Whiting 168,584 48.73%
Prohibition James Michelwait 1,412 0.41%
Greenback Elias Doty 314 0.09%
Majority 7,021
Turnout
Republican hold Swing

References

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  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 15, 2020.