1928 World Table Tennis Championships – Men's singles

1928 Men's singles
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Main article: 1928 World Table Tennis Championships

The 1928 World Table Tennis Championships men's singles was the second edition of the men's singles championship.[1][2] Zoltán Mechlovits met compatriot Laszlo Bellak in the final of this event. The latter won 8–21, 18–21, 24–22, 21–12, 21–15.

Draw

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Key

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  • Q = Qualifier
  • w/o = Walkover
  • w/d = Withdraw
  • r = Retired
  • DQ = Disqualified

Finals

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[2]

Round of 16 Quarterfinals Semifinals Final
Sweden Ragnar Söderholz 21 21 22
Czechoslovakia Kurt Heller 15 18 20 Sweden Ragnar Söderholz
Kingdom of Hungary Zoltán Mechlovits 21 21 21 Kingdom of Hungary Zoltán Mechlovits W⁄O
Latvia I. Rosenthal 9 18 16 Kingdom of Hungary Zoltán Mechlovits 21 21 21
Czechoslovakia Antonin Malecek 14 17 18 Austria Alfred Liebster 17 5 16
Austria Alfred Liebster 21 21 21 Austria Alfred Liebster 12 13 21 21 21
Kingdom of Hungary Sándor Glancz 21 21 21 Kingdom of Hungary Sándor Glancz 21 21 18 13 18
England Charles Allwright 15 7 17 Kingdom of Hungary Zoltán Mechlovits 8 18 24 21 21
England Fred Perry 21 21 14 21 Kingdom of Hungary Laszlo Bellak 21 21 22 12 15
Czechoslovakia Erwin Fleischmann 9 7 21 14 England Fred Perry 7 19 16
Kingdom of Hungary Laszlo Bellak 21 21 17 21 Kingdom of Hungary Laszlo Bellak 21 21 21
Sweden Valter Kolmodin 13 13 21 11 Kingdom of Hungary Laszlo Bellak 21 21 21
England Adrian Haydon 26 18 22 21 Austria Paul Flussmann 10 19 14
Kingdom of Hungary Roland Jacobi 24 21 20 16 England Adrian Haydon 16 21 12 18
Wales Trevor Coles 12 21 19 Austria Paul Flussmann 21 16 21 21
Austria Paul Flussmann 21 23 21

References

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  1. ^ "List of Winners". All About Tennis.
  2. ^ a b "1928 results" (PDF). International Table Tennis Federation. Archived from the original (PDF) on 2012-04-12.
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