1989 Spanish Open – Doubles

Doubles
1989 Spanish Open
1988 ChampionsCzechoslovakia Iva Budařová
Belgium Sandra Wasserman
Final
ChampionsCzechoslovakia Jana Novotná
Denmark Tine Scheuer-Larsen
Runners-upSpain Arantxa Sánchez
Austria Judith Wiesner
Score6–2, 2–6, 7–6
Details
Draw16
Seeds4
Events
Singles Doubles
← 1988 · Spanish Open · 1990 →

Iva Budařová and Sandra Wasserman were the defending champions but did not compete that year.

Jana Novotná and Tine Scheuer-Larsen won in the final 6–2, 2–6, 7–6 against Arantxa Sánchez and Judith Wiesner.

Seeds

[edit]

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1. Czechoslovakia Jana Novotná / Denmark Tine Scheuer-Larsen (champions)
  2. Canada Helen Kelesi / France Catherine Suire (semifinals)
  3. Spain Arantxa Sánchez / Austria Judith Wiesner (final)
  4. France Sophie Amiach / France Alexia Dechaume (semifinals)

Draw

[edit]

Key

[edit]
First round Quarterfinals Semifinals Final
1
6 6  
 
3 3   1
6 6  
 
6 6    
2 0  
 
1 3   1
6 7  
4
6 7   4
2 6  
 
2 5   4
6 6  
 
4 3    
4 3  
 
6 6   1
6 2 7
 
1 7 5 3
2 6 6
 
6 5 7  
2 2  
 
0 0   3
6 6  
3
6 6   3
6 6  
 
6 5 6 2
2 1  
 
4 7 3  
4 2  
 
3 1   2
6 6  
2
6 6  
[edit]
Retrieved from "https://en.wikipedia.org/w/index.php?title=1989_Spanish_Open_–_Doubles&oldid=1255079230"