2006 Stella Artois Championships – Doubles

Doubles
2006 Queen's Club Championships
Final
Champions
Runners-up
Score6–4, 3–6, [10–8]
Details
Draw24
Events
Singles Doubles
← 2005 · Queen's Club Championships · 2007 →

Bob Bryan and Mike Bryan were the defending champions, but lost in the semifinals this year.

Paul Hanley and Kevin Ullyett won in the final 6–4, 3–6, [10–8], against Jonas Björkman and Max Mirnyi.

Seeds

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All seeds receive a bye into the second round.

  1. United States Bob Bryan / United States Mike Bryan (semifinals)
  2. Sweden Jonas Björkman / Belarus Max Mirnyi (final)
  3. The Bahamas Mark Knowles / Canada Daniel Nestor (semifinals)
  4. Australia Paul Hanley / Zimbabwe Kevin Ullyett (champions)
  5. Australia Stephen Huss / South Africa Wesley Moodie (second round)
  6. Czech Republic František Čermák / Czech Republic Leoš Friedl (quarterfinals)
  7. Zimbabwe Wayne Black / South Africa Jeff Coetzee (quarterfinals)
  8. Australia Wayne Arthurs / United States Justin Gimelstob (quarterfinals)

Draw

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Key

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Finals

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Semifinals Final
          
1 5 64  
4 7 77  
4 6 3 [10]
2 4 6 [8]
3 77 64 [7]
2 65 77 [10]

Top half

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First round Second round Quarterfinals Semifinals
1 77 6  
  6 3 [10]   60 4  
  3 6 [6] 1 65 78 [10]
  4 6 [10] 8 77 66 [7]
  6 3 [2]        
8 w/o    
1 5 64  
4 7 77  
4 3 7 [10]
  78 6     6 5 [6]
  66 3   4 6 6  
  4 77 [11] 7 4 2  
  6 61 [9]   6r    
7 5    

Bottom half

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First round Second round Quarterfinals Semifinals
6 w/o    
  3 62          
  6 77   6 5 4  
  3 6 [9] 3 7 6  
  6 2 [11]   77 66 [11]
3 64 78 [13]
3 77 64 [7]
2 65 77 [10]
5 4 65  
  5 65   WC 6 77  
WC 7 77   WC 64 2  
  3 63   2 77 6  
WC 6 77   WC 77 4 [6]
2 64 6 77
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