2007 ASB Classic – Singles

From Wikipedia the free encyclopedia

Singles
2007 ASB Classic
Final
ChampionSerbia Jelena Janković
Runner-upRussia Vera Zvonareva
Score7–6(11–9), 5–7, 6–3
Details
Draw32
Seeds8
Events
Singles Doubles
← 2006 · ASB Classic · 2008 →

Marion Bartoli was the defending champion, but lost in the second round against Émilie Loit.

Jelena Janković won the title, beating Vera Zvonareva 7–6(11–9), 5–7, 6–3 in the final.[1][2][3]

Draw[edit]

Seeds[edit]

  1. Serbia Jelena Janković (champion)
  2. Russia Anastasia Myskina (first round)
  3. Slovakia Daniela Hantuchová (second round)
  4. France Marion Bartoli (second round)
  5. Russia Vera Zvonareva (final)
  6. Germany Martina Müller (first round)
  7. Greece Eleni Daniilidou (quarterfinals)
  8. United States Shenay Perry (first round)

Key[edit]

Finals[edit]

Semifinals Final
          
1 Serbia Jelena Janković 3    
  France Camille Pin 0r  
1 Serbia Jelena Janković 7 5 6
5 Russia Vera Zvonareva 69 7 3
5 Russia Vera Zvonareva 6 7  
  United States Jill Craybas 3 5  

Top half[edit]

First round Second round Quarterfinals Semifinals
1 Serbia J Janković 6 6  
  Germany J Schruff 3 4   1 Serbia J Janković 6 6  
LL France M Johansson 64 1     Finland E Laine 2 1  
  Finland E Laine 7 6   1 Serbia J Janković 6 6  
WC New Zealand M Erakovic 6 4 7 7 Greece E Daniilidou 3 4  
Q United States M Tu 3 6 5 WC New Zealand M Erakovic 4 6 4
  Croatia J Kostanić 3 6 1 7 Greece E Daniilidou 6 4 6
7 Greece E Daniilidou 6 4 6 1 Serbia J Janković 3    
4 France M Bartoli 7 6     France C Pin 0r    
  Japan A Morita 64 3   4 France M Bartoli 5 4  
  Czech Republic E Birnerová 1 1     France É Loit 7 6  
  France É Loit 6 6     France É Loit 3 3  
Q Austria Y Meusburger 7 6     France C Pin 6 6  
  Russia E Bychkova 5 0   Q Austria Y Meusburger 6 3 3
  France C Pin 6 5 6   France C Pin 2 6 6
8 United States S Perry 3 7 2

Bottom half[edit]

First round Second round Quarterfinals Semifinals
5 Russia V Zvonareva 5 6 6
Q United States L Osterloh 7 2 3 5 Russia V Zvonareva 6 6  
  Italy R Oprandi 3 4     United States L Granville 3 4  
  United States L Granville 6 6   5 Russia V Zvonareva 7 2  
Q France V Razzano 7 6   Q France V Razzano 5 0r
  Estonia K Kanepi 61 1   Q France V Razzano 6 7  
  Slovakia D Cibulková 1 6 2 3 Slovakia D Hantuchová 1 5  
3 Slovakia D Hantuchová 6 3 6 5 Russia V Zvonareva 6 7  
6 Germany M Müller 6 1 1   United States J Craybas 3 5  
  Argentina P Suárez 3 6 6   Argentina P Suárez 7 6  
WC New Zealand L Baker 1 1     China T Sun 5 4  
  China T Sun 6 6     Argentina P Suárez 3 64  
  United States J Craybas 7 6     United States J Craybas 6 7  
  Japan A Nakamura 5 2     United States J Craybas 6 7  
  Argentina G Dulko 6 64 6   Argentina G Dulko 3 5  
2 Russia A Myskina 1 7 2

References[edit]

  1. ^ "Jankovic claims crown". Eurosport. 6 January 2007.
  2. ^ "Jankovic tops Zvonareva in Auckland final". UPI. 6 January 2007.
  3. ^ "2007 Auckland - ITF tournament draws". International Tennis Federation (ITF).

External links[edit]